(25x^-3*Y^2)/(35x^5*Y^4)=1

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Solution for (25x^-3*Y^2)/(35x^5*Y^4)=1 equation: 


D( x )

35*Y^4*x^5 = 0

x = 0

35*Y^4*x^5 = 0

35*Y^4*x^5 = 0

35*Y^4*x^5 = 0 // : 35*Y^4

x^5 = 0

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(25*Y^2*x^-3)/(35*Y^4*x^5) = 1 // - 1

(25*Y^2*x^-3)/(35*Y^4*x^5)-1 = 0

5/7*Y^-2*x^-8 = 1 // : 5/7*Y^-2

x^-8 = 7/5*Y^2

-8 < 0

1/(x^8) = 7/5*Y^2 // * x^8

1 = 7/5*Y^2*x^8 // : 7/5*Y^2

5/7*Y^-2 = x^8

x^8 = 5/7*Y^-2 // ^ 1/8

abs(x) = (5/7)^(1/8)*Y^(-1/4)

x = (5/7)^(1/8)*Y^(-1/4) or x = -((5/7)^(1/8)*Y^(-1/4))

x in { (5/7)^(1/8)*Y^(-1/4), -((5/7)^(1/8)*Y^(-1/4)) }

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